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ST7DALI Datasheet(PDF) 71 Page - STMicroelectronics |
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ST7DALI Datasheet(HTML) 71 Page - STMicroelectronics |
71 / 141 page ST7DALI 71/141 DALI COMMUNICATION MODULE (Cont’d) 11.4.3 DALI Standard Protocol The DALI protocol uses the bi-phase Manchester asynchronous serial data format. All the bits of the frame are bi-phase encoded except the two stop bits. ■ The transmission rate is about 1.2 kHz. The bi- phase bit period is 833.33 us ±10%. ■ A forward frame consists of 19 bi-phase encoded bits: – 1 start bit (0->1: logical ’1’) – 1 address byte (8-bit address) – 1 data byte (8-bit data) – 2 high level stop bits (no change of phase) ■ A backward frame consists of 11 bi-phase encoded bits: – 1 start bit (0->1: logical ’1’) – 1 data byte (8-bit data) – 2 high level stop bits (no change of phase) A forward frame consists of 19 bi-phase encoded bits: 1 start bit (logical ’1’), 1 address byte and 1 data byte. The frame is terminated by 2 stop bits (idle). The stop bits do not contain any change of phase. A backward frame consists of 11 bi-phase encod- ed bits: 1 start bit (logical ’1’) and 1 data byte. The frame is terminated by 2 stop bits (idle). The stop bits do not contain any change of phase. The transmission rate, expressed as a bandwidth, is specified at 1.2 kHz for the forward channel and for the backward channel. The settling time between two subsequent forward frames is 9.17 ms (minimum). The settling time between forward and backward frames is between 2.92 ms and 9.17 ms. If a back- ward frame has not been started after 9.17 ms, this is interpreted as "no answer". In the event of code violation, the frame is ignored. After a code violation has occurred, the system is ready again for data reception. Figure 42. DALI Standard Frame a7 d7 a6 a5 a4 a3 a2 a1 a0 d6 d5 d4 d3 d2 d1 d0 2T 2T 2T 2T 2T 2T 2T 2T 2T 2T 2T 2T 2T 2T 2T 2T 2T 4T stop bits start bit address byte data byte FORWARD FRAME d7 d6 d5 d4 d3 d2 d1 d0 2T 2T 2T 2T 2T 2T 2T 2T 2T start bit data byte BACKWARD FRAME stop bits 4T BI-PHASE LEVELS Logical ’1’ Logical ’0’ 2T 2T 2T = 833.33 us ±10% 1 |
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