MC33364D1R2G datasheet(11/16 Pages) ONSEMI

Part #	MC33364D1R2G

Description	Critical Conduction GreenLine TM SMPS Controller

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Manufacturer	ONSEMI [ON Semiconductor]

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MC33364

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11

The MOC8102 has a typical current transfer ratio (CTR)

of 100% with 25% tolerance. When the TL431 is full−on,

5 mA will be drawn from the transistor within the

MOC8102. The transistor should be in saturated state at that

time, so its collector resistor must be

R

collector +

V

ref *

Vsat

I

LED

+ 5.0 V * 0.3 V

5.0 mA

+ 940 W

Since a resistor of 5.0 k is internally connected from the

reference voltage to the feedback pin of the MC33364, the

external resistor can have a higher value

Rext + R3 +

(R

int

)(R

collector

)

(R

int

)

* (R

collector

)

+

(5.0 k)(940)

5.0 k

* 940

+ 1157 W [ 1200 W

This completes the design of the voltage feedback circuit.

In no load condition there is only a current flowing

through the optoisolator diode and the voltage sense divider

on the secondary side.

The load at that condition is given by:

R

noload +

Vout

(I

LED )

I

div

)

+

6.0 V

(5.0 mA

) 0.25 mA) +

1143

W

The output filter pole at no load is:

f

ph +

1

(2

p R

noload

Cout )

+

1

(2

p)(1143)(300 mF) +

0.46 Hz

In heavy load condition the ILED and Idiv is negligible. The

heavy load resistance is given by:

R

heavy +

Vout

Iout

+ 6.0 V

2.0 A

+ 3.0 W

The output filter pole at heavy load of this output is

f

ph +

1

(2

p R

heavy

Cout)

+

1

(2

p)(3)(300 mF) +

177 Hz

The gain exhibited by the open loop power supply at the

high input voltage will be:

A

+

V

in max *

Vout

2

Ns

(V

in max

)(Verror)(Np)

+

(382 V

* 6.0 V)

2

(7)

(382 V)(1.2 V)(139)

+ 15.53 + 23.82 dB

The

maximum

recommended

bandwidth

is

approximately:

fc +

fs min

5

+ 70 kHz

5

+ 14 kHz

The gain needed by the error amplifier to achieve this

bandwidth is calculated at the rated load because that yields

the bandwidth condition, which is:

Gc

+ 20 log

fc

f

ph

* A + 20 log 14 kHz

177

* 23.82 dB

+ 14.14 dB

The gain in absolute terms is:

Ac + 10

(Gc 20) + 10(14.14 20) + 5.1

Now the compensation circuit elements can be calculated.

The output resistance of the voltage sense divider is given by

the parallel combination of resistors in the divider:

R

in +

Rupper || Rlower + 10 k || 14 k + 5833 W

R9

+ (Ac) (R

in

)

+ 29.75 k [ 30 k

C8

+

1

2

p (Ac)(R

in

)(fc)

+ 382 pF [ 390 pF

The compensation zero must be placed at or below the

light load filter pole:

C7

+

1

2

p (R9) (fpn)

+ 11.63 mF [ 10 mF

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