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DG406DW-E3 Datasheet(PDF) 10 Page - Vishay Siliconix

Part # DG406DW-E3
Description  16-Ch/Dual 8-Ch High-Performance CMOS Analog Multiplexers
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Manufacturer  VISHAY [Vishay Siliconix]
Direct Link  http://www.vishay.com
Logo VISHAY - Vishay Siliconix

DG406DW-E3 Datasheet(HTML) 10 Page - Vishay Siliconix

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Document Number: 70061
S-71009–Rev. I, 14-May-07
Vishay Siliconix
DG406/407
APPLICATIONS HINTS
Sampling speed is limited by two consecutive events: the
transition time of the multiplexer, and the settling time of the
sampled signal at the output.
tTRANS is given on the data sheet. Settling time at the load
depends on several parameters: rDS(on) of the multiplexer,
source impedance, multiplexer and load capacitances,
charge injection of the multiplexer and accuracy desired.
The settling time for the multiplexer alone can be derived
from the model shown in Figure 5. Assuming a low
impedance signal source like that presented by an op amp or
a buffer amplifier, the settling time of the RC network for a
given accuracy is equal to n
τ:
The maximum sampling frequency of the multiplexer is:
(1)
where N = number of channels to scan
tSETTLING = nτ = n x rDS(on) x CD(on)
For the DG406 then, at room temp and for 12-bit accuracy,
using the maximum limits:
(2)
or
fs = 694 kHz
(3)
From the sampling theorem, to properly recover the original
signal, the sampling frequency should be more than twice
the maximum component frequency of the original signal.
This assumes perfect bandlimiting. In a real application
sampling at three to four times the filter cutoff frequency is a
good practice.
Therefore from equation 2 above:
(4)
From this we can see that the DG406 can be used to sample
16 different signals whose maximum component frequency
can be as high as 173 kHz. If for example, two channels are
used to double sample the same incoming signal then its
cutoff frequency can be doubled.
% ACCURACY
# BITS
N
0.25
8
6
0.012
12
9
0.0017
15
11
Figure 5. Simplified Model of One Multiplexer Channel
RS = 0
rDS(on)
VOUT
CD(on)
f
s
1
Nt
SETTLING
t
TRANS
+
()
----------------------------------------------------------
=
f
s
1
16 9
100
Ω
×
10
-12
F
×
() 300 10
-12
s
×
+
-------------------------------------------------------------------------------------------------------
=
f
c
1
4
---
f
s
×
173 kHz
==


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