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575200B00000G Datasheet(PDF) 10 Page - Aavid, Thermal Division of Boyd Corporation |
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575200B00000G Datasheet(HTML) 10 Page - Aavid, Thermal Division of Boyd Corporation |
10 / 116 page 10 EUROPE ASIA Italy Tel: +39 051 764011 email: sales.it@aavid.com United Kingdom Tel: +44 1793 401400 email: sales.uk@aavid.com Singapore Tel: +65 6362 8388 email: sales@aavid.com.sg Taiwan Tel: +886(2) 2698-9888 email: sales@aavid.com.tw AMERICA USA Tel: +1 (603) 224-9988 email: info@aavid.com www.aavidthermalloy.com Find a heat sink to keep a TO-220 device below the maximum 150 °C junction temperature in forced convection at 400 ft/min. Device must be electrically insulated and mounted with a labor saving clip. Given: PD = 12 watts RθJC = 2.5°C/W (from semiconductor manufacturer) TJ max = 140°C (from semiconductor manufacturer) TA max = 50°C A Hi-Flow® pad works great with clip mounting and provides the necessary electrical insulation. Thermal resistance for Hi-Flow® at low pressure is 1.15°C/W (from page 87). Using equation 1, solve for RθSA RθSA = 140 – 50 - (2.5 + 1.15) = 3.85°C/W 12 Many styles are available. If board space is a concern, 533202B02551G (pg 55) meets the requirements. According to the above graph, an airflow of 400 ft/min results in a thermal resistance of 3°C/W. This is less than the required thermal resistance of 3.85°C/W and is therefore acceptable under these airflow conditions. If height is a concern, 533702B02552G would meet the requirements and is only 1.0” tall Find a space saving heat sink to keep a TO-220 device below the maximum 150°C junction temperature in natural convection. Device will be screw mounted with an electrically conductive interface. Given: PD = 6 watts RθJC = 3°C/W (from semiconductor manufacturer) TJ max = 150°C (from semiconductor manufacturer) TA max = 65°C A KonduxTM pad is a good choice for electrically conductive applications. Thermal resistance for KonduxTM can be determined from the following graph. Example B Example A Typical TO-220 Performance Screw Torque (in-lb) 0.00 012 3 4 5 0.10 0.20 0.30 0.40 0.50 0.60 6 How To Select a Heat Sink At 2 in-lb of torque the thermal resistance is approximately RθCS = 0.5°C/W Using equation 1, solve for RθSA RθSA = 150 – 65 - ( 3 + 0.5) = 10.7°C/W 6 The Index by Heat Sink Style on page 8 lists space saving heat sinks. Several models are in the 10 °C/W range. Choose the one that best fits the application and verify thermal resistance from graph. Part number 593202B03500G shows a 60 °C temperature rise at 6 watts. RθSA = 60 = 10.0°C/W 6 Which meets the above requirement in natural convection. Air Velocity—Feet Per Minute Heat Dissipated—Watts 10 0 20 40 60 80 100 0 2 4 6 8 10 8 6 2 4 0 0 400 200 600 800 1000 Air Velocity—Feet Per Minute Heat Dissipated—Watts 10 0 20 40 60 80 100 02 4 6 8 10 8 6 2 4 0 0 400 200 600 800 1000 53330X 53320X Hi-Flow® is a trademark of the Bergquist Company |
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