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ADP3088ARM Datasheet(PDF) 8 Page - Analog Devices

Part # ADP3088ARM
Description  1 MHz, 750 mA Buck Regulator
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Manufacturer  AD [Analog Devices]
Direct Link  http://www.analog.com
Logo AD - Analog Devices

ADP3088ARM Datasheet(HTML) 8 Page - Analog Devices

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ADP3088
–8–
REV. PrK
PRELIMINARY TECHNICAL DATA
amplifier, its frequency response limitation (i.e., as ad-
equately modeled by a capacitance from output to ground)
its external termination impedance (i.e., the compensation,
that may or may not include DC feedback), the modulator
transconductance, and the power converter's termination
impedance (i.e., the output capacitor and load resistance).
Since the ADP3088 has a current controlled loop, the par-
ticular inductor value does not by first order consideration
affect small signal stability. However, slew rate limitations
as discussed earlier - a large signal limitation consideration -
set boundaries that are often relevant for optimizing com-
pensation of the feedback loop. If the compensation of the
current control signal, i.e., the COMP pin, is designed to
promote a current response that is faster than the inductor
current can slew, then when a step load is applied the con-
trol signal will tend to initially respond in excess (of the
actual current change that is occurring) and then allow an
overshoot of the current and output voltage as it is delayed
in correcting its excess.
For conventional loads, the following describes how the
frequency corners (poles and zeroes) are positioned or
should be chosen to optimize the loop gain, beginning in
the low frequency spectrum:
1. The DC loop gain is limited by the applied load resis-
tance and the output resistance of the error amplifier,
but it is not important to determine how high the DC
gain is.
2. Two poles in the LF spectrum begin to roll off the gain,
one determined by the load resistance and output ca-
pacitor, CO, and the other by the error amplifier's out-
put resistance and its termination capacitance - the
equivalent feedback capacitance and the added com-
pensation capacitance CHF; determining the location of
these poles is not relevant to compensation design - it
suffices to know that both are decades below the cross-
over frequency.
3. A lead network is especially desirable for a variable out-
put voltage application in order to keep a fairly constant
crossover frequency and phase margin for all output
voltages; if used, this lead network consists of simply a
capacitor, CFF, in parallel with the upper feedback di-
vider resistor, RA; this creates a closely spaced zero/pole
pair that provides a gain boost before crossover so that,
above the pole frequency, the loop gain and phase are
similar for all output voltages; if the lead network is used
for a fixed voltage application, the pole should be cho-
sen to align with the following described zero; for vari-
able voltage applications, the maximum frequency of
the pole should be placed as high as is comfortable with-
out substantially degrading phase margin (e.g., not
within an octave or, more conservatively, a half decade
of the crossover frequency).
4. A zero turns the gain rolloff back to 1-pole sufficiently in
advance of the crossover frequency to create ample
phase margin, e.g., half a decade; the zero could feasi-
bly be that of the output capacitor itself - i.e., the zero
formed by the ESR and the capacitance CO - but that is
both unlikely (since the zero frequency will likely be
higher than where the loop zero is desired) and gener-
ally imprudent (since the loop performance would de-
pend on the stability of the ESR, which often is poor or
unknown); as recommended, the zero, fZ, is created by
an RC circuit terminating the COMP pin (a resistor, RC,
in series with a capacitor, CC), while the capacitance
terminating the error amplifier, CHF, forms a pole, fP,
with RC to cancel the zero of the output capacitor, or, if
the zero is well above the crossover frequency, as may
be the case when using an MLC output capacitor, that
pole is set high enough above the crossover frequency,
again e.g., half a decade, so that it doesn't cut substan-
tially into the phase margin at crossover, but still ensures
continued gain rolloff so that the gain margin is accept-
ably high; note that the previous guidelines suggest that
CC
≥ 10 × C
HF.
5. The gain crosses 0 dB (unity) at a crossover frequency
that is typically a tenth and advisably not greater than a
fourth of the switching frequency - one primary reason
for this approximate upper limit being the extra phase
margin loss due to the switching interval that is not pre-
dicted by the linear model.
Assuming no lead network is used, the open loop gain is
given by:
COMP
O
OL
OUT
V
ZZ
A
V
2
600 
µ×
×


(15)
where VOUT is the nominal DC level. This equation to-
gether with the preceding recommendations should suffice
to determine compensation component selection for users
familiar with loop design. This begins with deciding the
crossover frequency, fC, evaluating the impedances at that
frequency, and setting the open loop gain, AOL, to unity.
By example, fC = 125 kHz is chosen.
Assuming a well chosen CHF as described previously - i.e.,
such that it creates a pole well above crossover or approxi-
mately matches the zero of the output capacitor, the fol-
lowing equation approximates the calculation of the
crossover frequency:
()
()
1
1
150
/
1
21
/
Z
C
kA
f
k
f
kA
k
+Ω
×
×


=+
Ω×
(16)
where k1 = CO×VOUT/RC and fZ = 1/2
πRCCC - the zero
frequency set by the compensation - and the units are
shown with the constants in the equation for clarification.
The preceding equation cannot readily be solved in terms
of k1, but it can be solved closely enough by a few iterations
beginning with values for k1 around 1×10
9 (FA). For the
example below, set the zero about a half decade below fC as
previously advised, that is, choose fZ ~ fC /
√10 = 40 kHz.
Using the previously stated values for fZ and fC, the value of
k1 = 800 p(FA) satisfies the equation. RA and RB are pre-
sumed to be already chosen per earlier guidelines to set the
output voltage. As an example, RA = RB = 10 k
Ω (imply-
ing an output voltage of 2.5 V). Similarly it is presumed
that CO was chosen; let CO = 15
µF. Then, finally, RC and
then also CC can be determined by rearrangement of
simple formulas previously given. The example yields RC ~
47 k
Ω and CC ~ 82 pF. Assuming an MLC output capaci-


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