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TPS60401DBVR Datasheet(PDF) 3 Page - Texas Instruments |
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TPS60401DBVR Datasheet(HTML) 3 Page - Texas Instruments |
3 / 28 page TPS60400, TPS60401, TPS60402, TPS60403 UNREGULATED 60mA CHARGE PUMP VOLTAGE INVERTER SLVS324A − JULY 2001 REVISED NOVEMBER 2004 3 WWW.TI.COM detailed description operating principle The TPS60400, TPS60401 charge pumps invert the voltage applied to their input. For the highest performance, use low equivalent series resistance (ESR) capacitors (e.g., ceramic). During the first half-cycle, switches S2 and S4 open, switches S1 and S3 close, and capacitor (C(fly)) charges to the voltage at VI. During the second half-cycle, S1 and S3 open, S2 and S4 close. This connects the positive terminal of C(fly) to GND and the negative to VO. By connecting C(fly) in parallel, CO is charged negative. The actual voltage at the output is more positive than −VI, since switches S1–S4 have resistance and the load drains charge from CO. C(fly) 1 µF S2 S1 S3 S4 CO 1 µF VO (−VI) GND VI GND Figure 1. Operating Principle charge-pump output resistance The TPS6040x devices are not voltage regulators. The charge pumps output source resistance is approximately 15 Ω at room temperature (with VI = 5 V), and VO approaches –5 V when lightly loaded. VO will droop toward GND as load current increases. VO = −(VI – RO × IO) R O [ 1 ƒosc C (fly) ) 4 2R SWITCH ) ESR CFLY ) ESR CO RO = output resistance of the converter efficiency considerations The power efficiency of a switched-capacitor voltage converter is affected by three factors: the internal losses in the converter IC, the resistive losses of the capacitors, and the conversion losses during charge transfer between the capacitors. The internal losses are associated with the IC’s internal functions, such as driving the switches, oscillator, etc. These losses are affected by operating conditions such as input voltage, temperature, and frequency. The next two losses are associated with the voltage converter circuit’s output resistance. Switch losses occur because of the on-resistance of the MOSFET switches in the IC. Charge-pump capacitor losses occur because of their ESR. The relationship between these losses and the output resistance is as follows: PCAPACITOR LOSSES + PCONVERSION LOSSES = IO2 × RO RSWITCH = resistance of a single MOSFET-switch inside the converter fOSC = oscillator frequency The first term is the effective resistance from an ideal switched-capacitor circuit. Conversion losses occur during the charge transfer between C(fly) and CO when there is a voltage difference between them. The power loss is: P CONV.LOSS + 1 2 C (fly) V 2 I * V 2 O ) 1 2 C O V 2 RIPPLE * 2V O V RIPPLE ƒosc (1) (2) |
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