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AD630SCHIPS Datasheet(PDF) 4 Page - Analog Devices |
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AD630SCHIPS Datasheet(HTML) 4 Page - Analog Devices |
4 / 8 page REV. C –4– AD630–Typical Performance Characteristics Figure 7. Channel-to-Channel Switch- Settling Characteristic Figure 9. Large Signal Inverting Step Response TWO WAYS TO LOOK AT THE AD630 The functional block diagram of the AD630 (see page 1) also shows the pin connections of the internal functions. An alternative architectural diagram is shown in Figure 10. In this diagram, the individual A and B channel preamps, the switch, and the inte- grator output amplifier are combined in a single op amp. This amplifier has two differential input channels, only one of which is active at a time. 11 15 2 20 19 18 17 8 7 12 14 13 9 10 RA 5k 2.5k RF 10k 1 16 2.5k +VS RB 10k SEL B SEL A B/A A B –VS Figure 10. Architectural Block Diagram HOW THE AD630 WORKS The basic mode of operation of the AD630 may be more easy to recognize as two fixed gain stages which may be inserted into the signal path under the control of a sensitive voltage comparator. When the circuit is switched between inverting and noninverting gain, it provides the basic modulation/demodulation function. The AD630 is unique in that it includes Laser-Wafer-Trimmed thin- film feedback resistors on the monolithic chip. The configuration shown in Figure 11 yields a gain of ±2 and can be easily changed to ±1 by shifting RB from its ground connection to the output. The comparator selects one of the two input stages to complete an operational feedback connection around the AD630. The deselected input is off and has negligible effect on the operation. A B RA 5k RF 10k VO RB 10k Vi 2 20 19 18 13 15 16 14 9 10 Figure 11. AD630 Symmetric Gain ( ±2) When channel B is selected, the resistors RA and RF are con- nected for inverting feedback as shown in the inverting gain configuration diagram in Figure 12. The amplifier has sufficient loop gain to minimize the loading effect of RB at the virtual ground produced by the feedback connection. When the sign of the comparator input is reversed, input B will be deselected and A will be selected. The new equivalent circuit will be the nonin- verting gain configuration shown below. In this case RA will appear across the op-amp input terminals, but since the amplifier drives this difference voltage to zero the closed loop gain is unaffected. The two closed loop gain magnitudes will be equal when RF/RA = 1 + RF/RB, which will result from making RA equal to RFRB/ (RF + RB) the parallel equivalent resistance of RF and RB. The 5k and the two 10k resistors on the AD630 chip can be used to make a gain of two as shown here. By paralleling the 10k resistors to make RF equal 5k and omitting RB the circuit can be programmed for a gain of ±1 (as shown in Figure 18a). These and other configurations using the on chip resistors present the inverting inputs with a 2.5k source impedance. The more complete AD630 diagrams show 2.5k resistors available at the noninverting inputs which can be conveniently used to mini- mize errors resulting from input bias currents. Figure 8. Small Signal Noninverting Step Response 20mV 500ns 20mV 100 90 10 0% 20mV/DIV (Vo) 20mV/DIV (Vi) TOP TRACE: Vo BOTTOM TRACE: Vi 100 90 10 0% 100mV 500ns 50mV 1mV 50mV/DIV (Vi) 1mV/DIV (A) TOP TRACE: Vi MIDDLE TRACE: SETTLING ERROR (A) BOTTOM TRACE: Vo 100mV/DIV (Vo) 100 90 10 0% 10V 10V 1mV TOP TRACE: Vi MIDDLE TRACE: SETTLING ERROR (B) BOTTOM TRACE: Vo 5 s 10V 20kHz (Vi) 1mV/DIV (B) 10V/DIV (Vo) 5k 10k 10k Vi CH A CH B 12 VO 2 20 19 18 13 9 10 14 16 15 12 CH A MIDDLE TRACE (A) 10k 10k VO BOTTOM TRACE TEKTRONIX 7A13 10k 1k 30pF 10k Vi TOP TRACE 2 20 13 14 15 12 CH A 10k 10k VO BOTTOM TRACE 10k Vi TOP TRACE (B) MIDDLE TRACE 10k HP5082-2811 20 2 13 14 15 |
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