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V048F080T030A Datasheet(PDF) 11 Page - Vicor Corporation

Part # V048F080T030A
Description  High Efficiency, Sine Amplitude Converter
Download  18 Pages
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Manufacturer  VICOR [Vicor Corporation]
Direct Link  http://www.vicorpower.com
Logo VICOR - Vicor Corporation

V048F080T030A Datasheet(HTML) 11 Page - Vicor Corporation

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Not Recommended for New Designs
VTM® Current Multiplier
Rev 1.1
vicorpower.com
Page 11 of 18
02/2015
800 927.9474
V048x080y030A
11.0 SINE AMPLITUDE CONVERTERTM POINT OF LOAD CONVERSION
The Sine Amplitude Converter (SAC) uses a high frequency
resonant tank to move energy from input to output. (The
resonant tank is formed by Cr and leakage inductance Lr in the
power transformer windings as shown in the VTM module
Block Diagram. See Section 10). The resonant LC tank,
operated at high frequency, is amplitude modulated as a
function of input voltage and output current. A small amount
of capacitance embedded in the input and output stages of
the module is sufficient for full functionality and is key to
achieving power density.
The V048x080y030A SAC can be simplified into the following
model:
At no load:
VOUT = VIN K
(1)
K represents the “turns ratio” of the SAC.
Rearranging Eq (1):
K=
VOUT
(2)
VIN
In the presence of load, VOUT is represented by:
VOUT = VIN K – IOUT ROUT
(3)
and IOUT is represented by:
IOUT =
IIN –IQ
(4)
K
ROUT represents the impedance of the SAC, and is a function of
the RDSON of the input and output MOSFETs and the winding
resistance of the power transformer. IQ represents the
quiescent current of the SAC control and gate drive circuitry.
The use of DC voltage transformation provides additional
interesting attributes. Assuming that ROUT = 0 Ω and IQ = 0 A,
Eq. (3) now becomes Eq. (1) and is essentially load
independent, resistor R is now placed in series with VIN as
shown in Figure 15.
The relationship between VIN and VOUT becomes:
VOUT = (VIN –IIN R) K
(5)
Substituting the simplified version of Eq. (4)
(IQ is assumed = 0 A) into Eq. (5) yields:
VOUT = VIN K – IOUT R K2
(6)
+
+
VOUT
COUT
VIN
V•I
K
+
+
CIN
IOUT
RC
OUT
IQ
ROUT
RC
IN
88 mA
1/6 • IOUT
1/6 • VIN
6.8 m
Ω
RCIN
0.57 m
Ω
470 pH
0.5
Ω
RCOUT
400 µ
Ω
41 µF
LOUT = 600 pH
2 µF
IQ
LIN = 5.7 nH
IOUT
ROUT
VIN
VOUT
R
SAC
K = 1/32
Vin
Vout
+
VIN
VOUT
R
SAC™
K = 1/32
Figure 15 — K = 1/32 Sine Amplitude Converter™
with series input resistor
Figure 14 — VI Chip
® module AC model
COUT
CIN


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